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ICS8535I-21 Datasheet(PDF) 8 Page - Integrated Device Technology |
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ICS8535I-21 Datasheet(HTML) 8 Page - Integrated Device Technology |
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8 / 14 page ![]() ICS8535I-21 LOW SKEW, 1-TO-2 LVCMOS/LVTTL-TO-3.3V LVPECL FANOUT BUFFER IDT™ / ICS™ 3.3V LVPECL FANOUT BUFFER 8 ICS8535AGI-21 REV. A NOVEMBER 24, 2008 Application Information Recommendations for Unused Input and Output Pins Inputs: CLK Inputs For applications not requiring the use of a clock input, it can be left floating. Though not required, but for additional protection, a 1k Ω resistor can be tied from the CLK input to ground. LVCMOS Control Pins All control pins have internal pull-ups or pull-downs; additional resistance is not required but can be added for additional protection. A 1k Ω resistor can be used. Outputs: LVPECL Outputs All unused LVPECL outputs can be left floating. We recommend that there is no trace attached. Both sides of the differential output pair should either be left floating or terminated. Termination for 3.3V LVPECL Outputs The clock layout topology shown below is a typical termination for LVPECL outputs. The two different layouts mentioned are recommended only as guidelines. FOUT and nFOUT are low impedance follower outputs that generate ECL/LVPECL compatible outputs. Therefore, terminating resistors (DC current path to ground) or current sources must be used for functionality. These outputs are designed to drive 50 Ω transmission lines. Matched impedance techniques should be used to maximize operating frequency and minimize signal distortion. Figures 2A and 2B show two different layouts which are recommended only as guidelines. Other suitable clock layouts may exist and it would be recommended that the board designers simulate to guarantee compatibility across all printed circuit and clock component process variations. Figure 2A. 3.3V LVPECL Output Termination Figure 2B. 3.3V LVPECL Output Termination V CC - 2V 50 Ω 50 Ω RTT Z o = 50Ω Z o = 50Ω FOUT FIN RTT = Z o 1 ((V OH + VOL) / (VCC – 2)) – 2 3.3V 125 Ω 125 Ω 84 Ω 84 Ω Z o = 50Ω Z o = 50Ω FOUT FIN |
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