STM32F107VB datasheet(92/108 Pages) STMICROELECTRONICS

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STM32F105xx, STM32F107xx

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6.4.2

Selecting the product temperature range

When ordering the microcontroller, the temperature range is specified in the ordering

information scheme shown in Table 62: Ordering information scheme.

Each temperature range suffix corresponds to a specific guaranteed ambient temperature at

maximum dissipation and, to a specific maximum junction temperature.

As applications do not commonly use the STM32F103xx at maximum dissipation, it is useful

to calculate the exact power consumption and junction temperature to determine which

temperature range will be best suited to the application.

The following examples show how to calculate the temperature range needed for a given

application.

Example 1: High-performance application

Assuming the following application conditions:

Maximum ambient temperature TAmax = 82 °C (measured according to JESD51-2),

IDDmax = 50 mA, VDD = 3.5 V, maximum 20 I/Os used at the same time in output at low

level with IOL = 8 mA, VOL= 0.4 V and maximum 8 I/Os used at the same time in output

at low level with IOL = 20 mA, VOL= 1.3 V

PINTmax = 50 mA × 3.5 V= 175 mW

PIOmax = 20 × 8 mA × 0.4 V + 8 × 20 mA × 1.3 V = 272 mW

This gives: PINTmax = 175 mW and PIOmax = 272 mW:

PDmax = 175 + 272 = 447 mW

Thus: PDmax = 447 mW

Using the values obtained in Table 61 TJmax is calculated as follows:

–

For LQFP100, 46 °C/W

TJmax = 82 °C + (46 °C/W × 447 mW) = 82 °C + 20.6 °C = 102.6 °C

This is within the range of the suffix 6 version parts (–40 < TJ < 105 °C).

In this case, parts must be ordered at least with the temperature range suffix 6 (see

Table 62: Ordering information scheme).

Example 2: High-temperature application

Using the same rules, it is possible to address applications that run at high ambient

temperatures with a low dissipation, as long as junction temperature TJ remains within the

specified range.

Assuming the following application conditions:

Maximum ambient temperature TAmax = 115 °C (measured according to JESD51-2),

IDDmax = 20 mA, VDD = 3.5 V, maximum 20 I/Os used at the same time in output at low

level with IOL = 8 mA, VOL= 0.4 V

PINTmax = 20 mA × 3.5 V= 70 mW

PIOmax = 20 × 8 mA × 0.4 V = 64 mW

This gives: PINTmax = 70 mW and PIOmax = 64 mW:

PDmax = 70 + 64 = 134 mW

Thus: PDmax = 134 mW

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