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IR3640MPBF Datasheet(PDF) 21 Page - International Rectifier |
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IR3640MPBF Datasheet(HTML) 21 Page - International Rectifier |
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21 / 32 page ![]() 06/15/2009 IR3640MPBF 21 The higher the crossover frequency, the potentially faster the load transient response. However, the crossover frequency should be low enough to allow attenuation of switching noise. Typically, the control loop bandwidth or crossover frequency is selected such that The DC gain should be large enough to provide high DC-regulation accuracy. The phase margin should be greater than 45o for overall stability. For this design we have: V in=12V V o=1.8V V osc=1.8V V ref=0.7V L o=0.33uH C o=10x47uF(ceramic) It must be noted here that the value of the capacitance used in the compensator design must be the small signal value. For instance, the small signal capacitance of the 47uF capacitor used in this design is 23uF at 1.8 V DC bias and 600 kHz frequency. It is this value that must be used for all computations related to the compensation. The small signal value may be obtained from the manufacturer’s datasheets, design tools or SPICE models. Alternatively, they may also be inferred from measuring the power stage transfer function of the converter and measuring the double pole frequency F LC and using equation (16) to compute the small signal C o. Table 2 The compensation type and location of F ESR versus Fo These result to: F LC=18.3kHz F ESR=2306kHz F s/2=300kHz Select crossover frequency: Fo=100kHz Since: F LC<Fo<FS/2<FESR, TypeIII is selected to place the pole and zeros. Detailed calculation of compensation TypeIII: Tantalum Ceramic F LC<Fo<FESR Type III Electrolytic Tantalum FLC<FESR<Fo<Fs/2 Type II Output Capacitor F ESR vs Fo Compensator Type Tantalum Ceramic F LC<Fo<FESR Type III Electrolytic Tantalum FLC<FESR<Fo<Fs/2 Type II Output Capacitor F ESR vs Fo Compensator Type () s o F F * 1/10 ~ 1/5 ≤ pF 160 : Select , pF 74 . 163 ; * * 2 1 nF 6 . 5 : Select nF, 57 . 5 ; * * 2 1 k 3.24 : Select k 3.25 ; * * * * * 2 : and , Calculate nF 2.2 C : Select kHz 300 * 0.5 and kHz 8.82 * 5 . 0 : Select kHz 567.1 sin 1 sin 1 kHz 17.63 sin 1 sin 1 70 Margin Phase Desired 3 3 3 3 3 4 4 3 1 4 3 3 7 3 4 3 3 7 3 2 1 2 2 o = = = = = = Ω = Ω = = = = = = = = Θ − Θ + = = Θ + Θ − = = Θ C C R F C C C R F C R R V C V C L F R C C R F F F F F F F F P Z in osc o o o s P Z Z o P o Z π π π Ω = Ω = = 130 : Select , 130 ; * * 2 1 : and , Calculate 10 10 2 7 10 9 8 10 R R F C R R R R P π |
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