PC915 datasheet(7/7 Pages) SHARP

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PC915

0.067ms(1/15ms)

wave 3.58MHz

Superposition

Vin Waveform

APL: Average Picture Level

µ F

PC915

Anode

Cathode

1029

2SA

2SA1029

470

Ω

AGC

AMP

Ω

100

µ F

Vin

1.2

Ω

VCC

DG, DP

Tester

Tr1, Tr2 : 2SA1029 or other same rank products

µ F

PC915

Anode

Cathode

470

Ω

AGC

AMP

100

µ F

Vin

VCC

230

Ω

Tr1

Tr2

1.2k

Ω

µ F

VOUT

VOUT = 2.3

= 2.3

Vin

VCC- VE

IB : DC flowed to infrared LED

is : AC flowed to infrared LED

VE : Emitter voltage of Tr2 (Between emitter and GND )

Test Circuit of Differential Gain vs. R E and Differential Phase vs. R E

s Application Example

( 2) Handle this product the same as with other integrated circuits against static electricity.

s Precautions for Use

and GND near the device in order to stabilize power supply line.

< Example of Circuit Setting >

( 1) Set for Gain

G = 2.3/ ( VCC -VE)

( 2) Set for Input Resistance

Set Ri on output impedance ( usually 75

Ω ) of a mounting equipment.

( 3) Set for R E

( 4) Set for Low Cut-off Frequency

Then set Ci with input impedance of by-pass diode on as much value as possible on

( 3) As for other general cautions, refer to the chapter “ Precautions for Use ”

Gain is represented by the following formula ;

When using on condition that Gain = 1, set VCC -VE on 2.3V. So that R 1 and R 2 is determined.

When there is no signal ( input signal : 0 ) , set I LED flowed into infrared LED on 10 mA.

Low cut-off frequency with C terminal capacitance, C C, is represented by the following

formula ;

f C= 100/C C( Hz )( CC :

µ F value )

condition that f C>1/ ( 2

π CiR )[R= R

R2/ ( R1+R2) ]

( 1) It is recommended that a by-pass capacitor of more than 0.01

µ F is added between V

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