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HCS12 Datasheet(PDF) 409 Page - Freescale Semiconductor, Inc |
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HCS12 Datasheet(HTML) 409 Page - Freescale Semiconductor, Inc |
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409 / 452 page ![]() S12CPUV2 Reference Manual, Rev. 4.0 Freescale Semiconductor 409 been misaligned, the queue would be ready to advance and the O cycle would be used to perform a program word fetch. In a single-chip system or in a system with the program in 16-bit memory, both the free cycle and the program fetch cycle take one bus cycle. In a system with the program in an external 8-bit memory, the O cycle takes one bus cycle when it appears as a free cycle, but it takes two bus cycles when used to perform a program fetch. In this case, the on-chip integration module freezes the CPU clocks long enough to perform the cycle as two smaller accesses. The CPU handles only 16-bit data, and is not aware that the 16-bit program access is split into two 8-bit accesses. To allow development systems to track events in the CPU12 instruction queue, two status signals (IPIPE[1:0]) provide information about data movement in the queue and about the start of instruction execution. A development system can use this information along with address and data information to externally reconstruct the queue. This representation of the queue can also track both the data and address buses. B.5.3 Stack Function Both the M68HC11 and the CPU12 stack nine bytes for interrupts. Since this is an odd number of bytes, there is no practical way to ensure that the stack will stay aligned. To ensure that instructions take a fixed number of cycles regardless of stack alignment, the internal RAM in M68HC12 MCUs is designed to allow single cycle 16-bit accesses to misaligned addresses. As long as the stack is located in this special RAM, stacking and unstacking operations take the same amount of execution time, regardless of stack alignment. If the stack is located in an external 16-bit RAM, a PSHX instruction can take two or three cycles depending on the alignment of the stack. This extra access time is transparent to the CPU because the integration module freezes the CPU clocks while it performs the extra 8-bit bus cycle required for a misaligned stack operation. The CPU12 has a “last-used” stack rather than a “next-available” stack like the M68HC11 CPU. That is, the stack pointer points to the last 16-bit stack address used, rather than to the address of the next available stack location. This generally has very little effect, because it is very unusual to access stacked information using absolute addressing. The change allows a 16-bit word of data to be removed from the stack without changing the value of the SP twice. To illustrate, consider the operation of a PULX instruction. With the next-available M68HC11 stack, if the SP = $01F0 when execution begins, |
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